Please wait for the animation to completely load.
How does the electric potential around a charged solid insulating sphere (with charge distributed throughout the volume of the sphere) compare with the electric potential around a charged conducting sphere? Move the test charge to map out the electric potential as a function of distance from the center (position is given in centimeters and electric potential is given in volts). Restart.
Now for the voltage inside the uniformly charged insulator. Here the electric field is Qr/(4πε0R3), where R is the radius of the sphere itself. In this case, to find the potential as a function of r, you again need to integrate V = - ∫ E • dr, but this time you must break up the integral and integrate from infinity to R using E = Q/4πε0r2 (to find the electric potential associated with getting all the charges to the surface of the sphere) and then integrate from R to r (an arbitrary point inside the sphere) using the expression for the electric field inside the insulating sphere.
Exploration authored by Anne J. Cox.
Script authored by Mario Belloni and Anne J. Cox.
© 2004 by Prentice-Hall, Inc. A Pearson Company